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The math challenge.

Posted: Mon Dec 12, 2005 1:05 pm
by Capm
Here are the rules:
Starting with a simple equation, each next one must become progressively more difficult.
Each equation must begin with the answer to the previous.
No answer may come out as 0.
No answer may come out as Infinity.
Altho both may be a "part" of the answer.
See how far it goes. :)

To keep things neat, put the answer to the previous in quotes (or code) brackets.

Soooo, to start things off:

Code: Select all

2
2+2=

Posted: Mon Dec 12, 2005 1:15 pm
by Admiral Thrawn
4-2 =

Posted: Mon Dec 12, 2005 1:38 pm
by fyrephlie

Code: Select all

2
2 x 4 =

Posted: Mon Dec 12, 2005 1:49 pm
by DCrazy
8^2=

Posted: Mon Dec 12, 2005 1:58 pm
by fyrephlie
to keep things moving...
Capm wrote:To keep things neat, put the answer to the previous in quotes (or code) brackets.

Code: Select all

64
where x=2

64(x^3) =

Posted: Mon Dec 12, 2005 4:35 pm
by Nirvana
Next is the English "challange"!

Posted: Mon Dec 12, 2005 4:52 pm
by Capm
Silence you! :P

Code: Select all

512
(where y=2)

512/y(41^4+371)

Posted: Mon Dec 12, 2005 5:08 pm
by fyrephlie

Code: Select all

723,489,792
a = 1
b = 2
c = 3
d = 5
e = 8
f = 13
g = 21
(fibonnacci continues through z by adding the previous two numbers to make the next variable)

solve (z(q/x)(g-f))^2

(that ought to keep you busy for a while):P

Posted: Mon Dec 12, 2005 6:07 pm
by Capm
fyrephlie your last answer was incorrect and your next equation doesn't conform to the rules.

Here I'll change the variable letter to make it less confusing

Posted: Mon Dec 12, 2005 8:28 pm
by Krom
You may want to rethink how you wrote that equation capm. Firefly simply stuck it into google and got that answer. Google calculates it as:
google wrote:(512 / 2) * ((41^4) + 371) = 723,489,792
Were you intending on calculating it as 512 / (2(41^4)+371))? (9.0583171628218356396658047111741e-5)

Posted: Mon Dec 12, 2005 8:30 pm
by Capm
Doh, you are right! I forgot a *couple* pairs of thingymajoodles. :P




(where y=2)

512/(y((41^4)+371))

Posted: Mon Dec 12, 2005 8:54 pm
by Vertigo 99
Image

Posted: Mon Dec 12, 2005 8:59 pm
by Capm
Oh come on, Lothar and Drakona haven't even hit the thread yet!

Posted: Mon Dec 12, 2005 9:52 pm
by Krom
Vertigo 99 wrote:Image
Being slightly proficient with a calculator does not make you a nerd, posting forum macros does.

Posted: Mon Dec 12, 2005 10:28 pm
by fyrephlie
Capm wrote:fyrephlie your last answer was incorrect and your next equation doesn't conform to the rules.

Here I'll change the variable letter to make it less confusing
my answer was right the way you wrote it... (per KCalc:))

and the next was supposed to be

723,489,792 - (z(q/x)(g-f))^2

Posted: Mon Dec 12, 2005 10:58 pm
by Vertigo 99
Krom wrote: Being slightly proficient with a calculator does not make you a nerd, posting forum macros does.
this post would have merit if there was any possible way i could believe you were being serious

Posted: Tue Dec 13, 2005 12:24 am
by fyrephlie
ok ... the fact that this is the DESCENT BULLETIN BOARD inherantly makes us all nerds... now someone answer my 'problem' so we can move on. :P

Posted: Tue Dec 13, 2005 2:17 am
by Drakona
fyrephlie -

723,489,792 - (z(q/x)(g-f))^2

723,489,792 - [ (196418) * (2584 / 75025) * (21 - 13) ]^2

723,489,792 - ( 4060352896 / 75025 )^2

(4072343618901120000 - 16486546847213506816) / 5628750625

-12414203228312386816 / 5628750625

I printed it like that for one reason and one reason only. That fraction is in lowest terms. Honest. I checked (the bottom prime factors easily). Holy schlamoly.

Couldn't have been bothered to make it come out an integer, could we? Jolly good friends with the rationals, now are we? ;)

Right back atcha.

-(12414203228312386816 / 5628750625) * (2543972374969249 / 48492981360595261) *
(232058125/26849557152500992)

Posted: Tue Dec 13, 2005 2:40 am
by DCrazy

Code: Select all

-1e18
(n = -1e18)

nx^3 - 2nx^2 + 3nx + 4n = 0

Solve for x.

Re: The math challenge.

Posted: Tue Dec 13, 2005 3:05 am
by Flabby Chick
I got lost at this point........
Capm wrote:2+2=

Posted: Wed Dec 14, 2005 12:35 am
by Lothar
DCrazy wrote:

Code: Select all

-1e18
Check that again.

The numerators have a combined 45 digits. The denominators have a combined 44 digits. This means your answer's magnitude should be within a couple orders of magnitude of 10 -- somewhere between .1 and 1000.

1,000,000,000,000,000,000 is not within this range.

Posted: Wed Dec 14, 2005 12:41 am
by DCrazy
Farking Google calculator. Since it didn't like the equation as it stood, I did it piecewise and used Notepad for scratch... when I copied/pasted I must have kept 1042 instead of making it 42.
DCrazy wrote:

Code: Select all

-1
-x^3 + 2x^2 - 3nx + 4n = 0

Solve for x.