Eienstein Defeated?

[TIGERassault]

Neo's post is much too overcomplicated!


This is a more detailed definition of E=mc2, as this allows for if the object is moving. The concept here is that as v would be equal to c, ie at the speed of light, it would make the equation n/(1-1), which is n/0, which is said to be infinite. Therefore, it would take an infinite amount of energy to make something move as fast as light.

On the other hand, I find the actual definition itself to also be sketchy in that regards, as photons, even though they don't have mass, move at a speed of c, and 0/0 is just as infinite!

[Munk]

On the other hand, I find the actual definition itself to also be sketchy in that regards, as photons, even though they don't have mass, move at a speed of c, and 0/0 is just as infinite!

This is because you use the wrong equation.
The right equation is:

E^2 = m^2 c^4 + p^2 c^2

where p is the momentum p of the object.

For resting particles there is p=0, thus E = m c^2.
For photons there is m=0, thus E = p c

[TIGERassault]

This is because you use the wrong equation.
The right equation is:

E^2 = m^2 c^4 + p^2 c^2

where p is the momentum p of the object.

For resting particles there is p=0, thus E = m c^2.
For photons there is m=0, thus E = p c

According to Wikipedia:

"with p being the relativistic momentum (ie. p = γp0 = mrel * v)"


So hey, the point is the exact same! In fact, both equations are the same too!

[Munk]

The way how to add up velocities lies in the special geometry of spacetime, which can be found by the statement that \"the speed of light is constant for any (unaccelerated) observer\".

The equation for energy as above is also a consequence of the same geometry of spacetime.

Thus the reason for \"always below speed of light\" is somewhat \"hidden\".

[TIGERassault]

Thus the reason for "always below speed of light" is somewhat "hidden".

Is that your way of saying "I don't know why Einstein's formulas said that something can't go faster than light, but I'll make a complex post anyway to make it seem like I know what I'm talking about", or are you actually going somewhere with this?

[Munk]

Everyone can believe what they want. Knowing relativity is nothing crucial for survival ^^

I haven't studied physics to tell you rubbish, but exploring relativity by yourself from the very beginning is a great experience. Because you know actually why things are as they are - and not because someone told so.

Of course relativity can be described in 100 words only _scetchy_ like \"infinite energy barrier\" or \"mass increase\". But if you have the time, it is worth to get the full view.

[Foil]

Thus the reason for "always below speed of light" is somewhat "hidden".

Is that your way of saying "I don't know why Einstein's formulas said that something can't go faster than light, but I'll make a complex post anyway to make it seem like I know what I'm talking about", or are you actually going somewhere with this?

No, you misunderstand. By "hidden", he means "indirectly seen". As in, "you have to go through some work involving spacetime geometry to get from the premise (constancy of the speed of light) to the conclusion (velocities must always be below the speed of light)."

As he said earlier, Munk is an actively working physicist. Don't let the language barrier (Munk, I think your English is actually quite good) confuse you.

[TIGERassault]

Everyone can believe what they want. Knowing relativity is nothing crucial for survival ^^

No, but it is pretty crucial for being able to join in in a conversation about it...

[Foil]

A couple of quick mathematical notes:

...n/0, which is said to be infinite.
...
On the other hand, I find the actual definition itself to also be sketchy in that regards, as photons, even though they don't have mass, move at a speed of c, and 0/0 is just as infinite!

You should be more careful with indeterminate forms like "n/0" and "0/0", by actually doing some limit evaluations. Those indeterminate forms don't necessarily represent "infinity". In fact, something which evaluates to "0/0" may actually diverge to infinity, or it might not exist... or it might even represent a finite number!

This is because you use the wrong equation.
The right equation is:

E^2 = m^2 c^4 + p^2 c^2

where p is the momentum p of the object.

For resting particles there is p=0, thus E = m c^2.
For photons there is m=0, thus E = p c

According to Wikipedia:

"with p being the relativistic momentum (ie. p = γp0 = mrel * v)"


So hey, the point is the exact same! In fact, both equations are the same too!

Not quite the same.

There's a subtle difference (analogous to the difference between the equations a=b and a^2=b^2). Munk is quite right that the more general, correct form is E^2 = m^2 c^4 + p^2 c^2. Using the other form for scenarios that give you indeterminate forms ("n/0", "0/0") can lead to some misunderstandings.

[Strife]

Ok.... When I said infinite \"fuel\" I don't think I said what I really meant. I didn't mean you would constantly have like a full tank of gas. I mean with A fusion Reaction for speed it could possibly have the potential to break said rules of space fabric and all that crap. Thats what I think anyway.

[SuperSheep]

Hear Hear Foil!!!

For Intsance, take this little ditty...

sin(X)/X


The limit as X approaches 0 is 1

[Foil]

Hehe, that one was fun to teach my calculus class.

Me:\"What's the limit of sin(x)/x as x->0?\"

Various students:
\"Well, sin(0)=0, so we have 0/x, so it's 0!\"
\"No, the denominator goes to zero, so it diverges to infinity!\"
\"Wait... the numerator goes to zero, so it's going to zero... but the denominator goes to zero, so it's going to infinity? The limit must not exist!\"

[TIGERassault]

You should be more careful with indeterminate forms like "n/0" and "0/0", by actually doing some limit evaluations. Those indeterminate forms don't necessarily represent "infinity". In fact, something which evaluates to "0/0" may actually diverge to infinity, or it might not exist... or it might even represent a finite number!

I know, but it's just a lot easier to call it infinity and leave it at that.

There's a subtle difference (analogous to the difference between the equations a=b and a^2=b^2). Munk is quite right that the more general, correct form is E^2 = m^2 c^4 + p^2 c^2. Using the other form for scenarios that give you indeterminate forms ("n/0", "0/0") can lead to some misunderstandings.

But trying to calculate p gives the same problem as in the other equation!

[Foil]

I know, but it's just a lot easier to call it infinity and leave it at that.

The point is that "calling it infinity" isn't necessarily correct. Something which evaluates to "0/0" isn't necessarily infinite (e.g. the sin(x)/x as x->0 example SuperSheep mentioned).

...the more general, correct form is E^2 = m^2 c^4 + p^2 c^2. Using the other form for scenarios that give you indeterminate forms ("n/0", "0/0") can lead to some misunderstandings.

But trying to calculate p gives the same problem in the other equation!

How so?

I assume you're talking about your earlier question about photons (rest mass=0)? As Munk said, that simplifies the equation to E=pc ( => p=E/c).

[TIGERassault]

I assume you're talking about your earlier question about photons (rest mass=0)? As munk said, that simplifies the equation to E=pc ( => p=E/c).

Hmm... I hadn't thought of that as p=E/c...
Ok, now I'm just confused.

[Munk]

But trying to calculate p gives the same problem in the other equation!

Yes, you see ? All those relativistic equations with the velocity v doesn't make sense, as you approach v -> c.
This is because m > 0 and v=c is contradictory.

Working with relativistic theory in this way shows you, that the velocity is not a "good" variable. With velocity involved, you need to seperate equations for massive and massless particles, the transition is somewhat obscure.
Working with momentum p is much simpler and equations holds for both (massive and massless).

This is a strong hint that the momentum p is more fundamental than the velocity, and in fact it is true:
Momentum p shares the spacetime geometry, while the velocity v does not!

Of course for human's life velocity is much more intuitive than momentum, but for relativistic physics it's the other way around ^^

[suicide eddie]

here we go ladies, further reading


http://arxiv.org/ftp/arxiv/papers/0708/0708.0681.pdf